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proemeth
on Dec 7, 2010
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On the evidence of a single coin toss
This is a bayesian problem, depending on the a priori probability given to a "special dice" pri,
P = 2 * pri / (1+pri)
(Which is > to the probability before tossing)
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P = 2 * pri / (1+pri)
(Which is > to the probability before tossing)